OT: how to get shell status of first pipe shell command (when fail), not that of the last one

[Dario Lesca]

When I concatenate 2 or more shell command with pipe (|), I get only
the status of last one.

For example: "some-cmd | logger -t "some-cmd messages:"; echo $?"

If "some-cmd" fail with status !=0 I get always status of last one, in
this case 0

In my case if the first command fail, I must send a warning message

A more simple example is: "false | true"

I want get status 1, of first command (false), not 0 (true)

I have also try "sh -e -c 'false || exit 2|true'; echo $?" but I get
always 0

How to I get first status and break the chains of pipes ?

Many thanks